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Vintage Unix news. Book "Understanding Linux: The Kernel Perspective" leanpub.com/linuxkernel/

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calendar_today31-12-2017 06:54:35

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14 days ago

In the bash source code, there is a “nofork” condition, which causes bash not to fork a child before executing a program. But why would bash want to execute a program without forking first? This is used by the bash exec built-in, which skips forking and calls execve() directly

In the bash source code, there is a “nofork” condition, which causes bash not to fork a child before executing a program. But why would bash want to execute a program without forking first? This is used by the bash exec built-in, which skips forking and calls execve() directly