π°π¦πͺπ¬π«.
@tvngibles
β β β β β β β β γγ¬γ³ giving π―πΆπΏππ΅ to a π£π’π£πΊ is eΜ΅aΜ΅sΜ΅iΜ΅eΜ΅rΜ΅ Μ΅ β β β β β β β β β β β β β β β β than πΈπ°π³π³πΊπͺπ―π¨ about π’π.
ID: 2898996419
30-11-2014 10:23:24
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