
Garrett
@polymathiceng
Aspiring Polymath.
x' = f(x)
CTO @Masterfile_co
ID: 1263242495674081281
http://Masterfile.co 20-05-2020 22:57:42
1,1K Tweet
223 Takipçi
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@polymathiceng
Aspiring Polymath.
x' = f(x)
CTO @Masterfile_co
ID: 1263242495674081281
http://Masterfile.co 20-05-2020 22:57:42
1,1K Tweet
223 Takipçi
313 Takip Edilen