Handy

🚀 #LeetCode POTD (Day 43) ✅ Construct String With Repeat Limit 💡 Approach (Heap) 1️⃣ Count character frequencies 2️⃣ Use a max-heap to pick the largest char 3️⃣ Append up to repeatLimit times 4️⃣ If chars remain, use the next largest char, then push back unused chars

🚀 #LeetCode POTD (Day 44) ✅ Final Prices With Special Discount 💡 Approach (Stack) 1️⃣ Traverse prices in reverse 2️⃣ Use stack to find nearest smaller price to right 3️⃣ Discount: prices[i] - stack.top() or prices[i] 4️⃣ Push current price onto stack

🚀 #LeetCode POTD (Day 45) ✅ Max Chunks To Make Sorted 💡 Approach 1️⃣ Track curr_max while iterating. 2️⃣ If curr_max == i, it’s a valid chunk end. 3️⃣ Increment chunk count and return total.

🚀 #LeetCode POTD (Day 47) ✅ Maximum Number of K-Divisible Components 💡 Approach (DFS) 1️⃣ Perform a DFS traversal to compute subtree sums. 2️⃣ If a subtree sum is divisible by k, it forms a valid component. 3️⃣ Increment component count (ans) and reset sum for that subtree.

🚀 #LeetCode POTD (Day 50) ✅ Find Minimum Diameter After Merging Two Trees 💡 Approach (BFS) 1️⃣ Compute diameters (d1, d2) of both trees using BFS. 2️⃣ Merged diameter: max(d1, d2, ⌈d1/2⌉ + ⌈d2/2⌉ + 1). 3️⃣ BFS twice finds the farthest nodes to calculate tree diameter.

🚀 #LeetCode POTD (Day 51) ✅ Find Largest Value in Each Tree Row 💡 Approach (Simple BFS) 1️⃣ Apply plain BFS to traverse the tree level by level. 2️⃣ At each level, store the maximum value in the result vector.

🚀 #LeetCode POTD (Day 52) ✅ Target Sum 💡 Approach (DP) 1️⃣ Use recursion with memoization to explore adding/subtracting nums[ind]. 2️⃣ Handle negatives by offsetting currSum with S = sum(nums). 3️⃣ Store results in dp[ind][currSum + S] to avoid recomputation and optimize.

🚀 #LeetCode POTD (Day 55) ✅ 💡 Approach (Dynamic Programming) 1️⃣ Precompute freq for char counts at each column in words 2️⃣ Use recursion + memoization to find ways to form target[i] starting from column j 3️⃣ Either skip or use column j, ensuring results are modulo 1e9 + 7

🚀 #LeetCode POTD (Day 56) ✅ 💡 Approach (Dynamic Programming) 1️⃣ Start recursion with curr_len = 0, check bounds [low, high], set addOne = true if valid 2️⃣ Count ways via recursive calls for take_one & take_zero 3️⃣ Return addOne + take_one + take_zero (total ways)

Leetcode December Batch 2024 ✅

🚀 #LeetCode POTD (Day 59) ✅ Count Vowel Strings in Ranges 💡 Approach (Prefix Sum) 1️⃣ Count words starting & ending with vowels, storing cumulative counts 2️⃣ For each query, use pf_sum[r] - pf_sum[l-1] formula 3️⃣ Store results for all queries

🚀 #LeetCode POTD (Day 61) ✅ 💡 Approach (Set + Two Pointers) 1️⃣ Identify first & last occurrence of each character. 2️⃣ Collect unique middle characters for valid ranges. 3️⃣ Return the count of unique palindromic subsequences.

🚀 #LeetCode POTD (Day 62) ✅ Shifting Letters II 💡 Approach (Difference Array Pattern) 1️⃣ Build difference array for range shifts. 2️⃣ Compute cumulative shifts with prefix sum. 3️⃣ Apply mod 26 to handle shifts (negative/large), wrapping 'a' to 'z' accordingly.

🚀 #LeetCode POTD (Day 65) ✅ 💡 Approach (Brute Force) 1️⃣ For each word pair (i, j) where i < j, check if the first word is both a prefix and suffix of the second. 2️⃣ Use find and rfind to verify prefix-suffix match. 3️⃣ Count and return total valid pairs.

🚀 #LeetCode POTD (Day 66) ✅ Counting Words With a Given Prefix 💡 Approach (String Matching) 1️⃣ Loop through the words, check if each starts with the prefix using starts_with(). 2️⃣ Increment a counter for each match and return the total.

🚀 #LeetCode POTD (Day 72) ✅ 💡 Approach (Bit Manipulation) 1️⃣ Count set bits in num1 & num2 using __builtin_popcount(). 2️⃣ If num1 has fewer set bits, turn on unset bits from LSB. 3️⃣ If num1 has more set bits, turn off set bits from LSB.

🚀 #LeetCode POTD (Day 73) ✅ 💡 Approach (Bit Manipulation) 1️⃣ Elements with even frequency cancel out: x ^ x = 0 2️⃣ If nums1.size() is odd, XOR all elements of nums2. 3️⃣ If nums2.size() is odd, XOR all elements of nums1. 4️⃣ Return the final XOR result.

You don't need to know everything to be a developer. You need just enough knowledge to ask the right questions and make meaningful progress.

🚀 #LeetCode POTD (Day 74) ✅ 💡 Approach (Bit Manipulation) : 1️⃣ In a circular XOR, original[0] repeats twice, so XOR of all derived must be 0. 2️⃣ Compute XOR of all derived elements. 3️⃣ Return true if XOR == 0, else false.