∫ 1/(x² + 9) dx = tan⁻¹(x/3)/3 + C (@e__eql__mcsq) 's Twitter Profile
∫ 1/(x² + 9) dx = tan⁻¹(x/3)/3 + C

@e__eql__mcsq

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calendar_today24-02-2023 07:14:56

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