clancy
@clancyhughes
quant, engineering, occasional USMNT musings…..… P(A|B) = (P(B|A)*P(A))/P(B), everything else is conjecture
ID: 768972748739620864
26-08-2016 00:46:04
7,7K Tweet
477 Takipçi
879 Takip Edilen
@clancyhughes
quant, engineering, occasional USMNT musings…..… P(A|B) = (P(B|A)*P(A))/P(B), everything else is conjecture
ID: 768972748739620864
26-08-2016 00:46:04
7,7K Tweet
477 Takipçi
879 Takip Edilen