いそべやん(@sbakbao) 's Twitter Profile Photo

f:X→Y
X'⊂X
の時、fによるX'の像をf(X')って表現するけど、このf(=f(X')に使われてるf)は
f:2^X→2^Y
なんだよね。これ紛らわしいので要注意。

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すがはら(@wwpqq) 's Twitter Profile Photo

細字(x,y)=(x',y') ⇔(x=x' et y=y')・・➀ はℑの定理
から
太字(𝙏,𝙐)=(𝙏',𝙐')⇔(𝙏=𝙏' et 𝙐=𝙐')   はℑの定理

を言うには、

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Rabbi Adolf Shayevich(@AdolfShayevich) 's Twitter Profile Photo

Taboo Gaby Another Dead Poet Dead Ferrets Premier League That would be an ∀x,y∈X,Y x>y || y>x => x=/=y, this NOT a tautology, this would be the tautology you are trying to demonstrate: ∀x,y∈X,Y: x, x>y && y>x => x=y
it its true for every possible interpretation then its a tautology. What I was demonstrating was the

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すがはら(@wwpqq) 's Twitter Profile Photo

イ)
wwpqq11のblog 2頁の
「P.68 命題1 細字字体 {{x},{x,y}}={{x'},{x',y'}} ⇔ (x=x' et y=y')」に

細字(x,y)=(x',y') ⇔(x=x' et y=y')・・➀ はℑの定理

の証明をメモ。

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bourbon, neat — thought criminal.(@bourbonneat5) 's Twitter Profile Photo

Because multiplication is really saying “add THIS to itself THAT many times.

x*y = x + x + … + x (where there are y number of x’s added together)

This is why multiplication comes before addition, unless the addition is inside parentheses.

Make sense?

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Tarkus(@SalhiTarek) 's Twitter Profile Photo

Analysis Fact A classical example of non-commutativity of limits when you are dealing with a non-summable family {n/m+n} over (N*)^2 (or, in an equivalent way, non-integrability of the function f(x,y)=x/(x+y) over [1,+oo[^2.

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Bryan Johnston(@BryanJohnston18) 's Twitter Profile Photo

Who-Else Garret Hohl Lek Good Sports Takes 1. Here’s a proof coefficient estimates in linear regression are unbiased:

E(b) = E((X'X)^(-1)(X'Y))
= (X'X)^(-1)X'E(Y)
= (X'X)^(-1)X'XB
= IB = B

Since bias = E(b) - B, we then have
bias = B - B = 0

Thus the vector of coefficient estimates in linear regression are unbiased.

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Amit N(@mcfc_amit) 's Twitter Profile Photo

Richard White World of Engineering Speed of plane : x ->this is generated by the thrust
Speed of conveyer : y
In this scenario: x= -y

Net speed of Plane= x+y
= x+(-x)
= 0

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Isaac Carcacía(@Isaaccarcacia) 's Twitter Profile Photo

En un monoide un idempotente distinto del elemento neutro no puede tener inverso, más concretamente si x*x=x entonces x*y=1 implica x=1. En efecto, puesto que por un lado x*x*y=(x*x)*y=x*y=1 y por otro x*x*y=x*(x*y)=x*1=x.

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Atko Amatarp(@otekpreketek1) 's Twitter Profile Photo

BURUANN CEK PINNED!!— SBMPTNFESS [1]

ingat translasi!

(x,y) digeser sejauh (a,b) menghasilkan bayangan di (x',y') = (x+a,y+b)

ganti (x,y) menjadi (x',y')
x = x'-a
y = y'-b

y = (x+1)² - 1
digeser sejauh (2,2) menjadi
y'-2 = (x'-2+1)² - 1
[hilangkan saja ' nya]
y = (x-1)² + 1 = g(x) ≥ 1
tidak memotong sb. x

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Tintxo Cariñena(@Tintxo40) 's Twitter Profile Photo

Juegos y Desafíos Matemáticos Conseguido.
Empezando del centro abajo.
x=derecha, y=arriba, d=diagonal
x x y d y -x -y -x -x y d y x y -x -y -x y d -x -y x y x x x -y d -y x -y -x y -x y

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